Reducer.Reducer<bigint>Reducer for combining bigints using multiplication.
When to use
Use to multiply many bigint values through APIs that consume a Reducer.
Details
The initial value is 1n, so combineAll([]) returns 1n.
export const const ReducerMultiply: Reducer.Reducer<bigint>const ReducerMultiply: {
initialValue: A;
combineAll: (collection: Iterable<A>) => A;
combine: (self: A, that: A) => A;
}
Reducer for combining bigints using multiplication.
When to use
Use to multiply many bigint values through APIs that consume a Reducer.
Details
The initial value is 1n, so combineAll([]) returns 1n.
ReducerMultiply: import ReducerReducer.interface Reducer<A>Represents a strategy for reducing a collection of values of type A into
a single result.
When to use
Use when you need to fold/reduce a collection into a single value.
- You want a reusable reducing strategy that can be passed to library
functions like
Struct.makeReducer, Option.makeReducer, or
Record.makeReducerUnion.
- You need both the combining logic and a known starting value.
Details
Extends
Combiner.Combiner
with:
initialValue – the identity/neutral element for combine.combineAll – folds an entire Iterable<A> from initialValue.
Many modules ship pre-built reducers:
Number.ReducerSum, Number.ReducerMultiplyString.ReducerConcatBoolean.ReducerAnd, Boolean.ReducerOr
Example (String concatenation reducer)
import { Reducer } from "effect"
const Concat = Reducer.make<string>((a, b) => a + b, "")
console.log(Concat.combineAll(["hello", " ", "world"]))
// Output: "hello world"
Reducer<bigint> = import ReducerReducer.function make<A>(
combine: (self: A, that: A) => A,
initialValue: A,
combineAll?: (collection: Iterable<A>) => A
): Reducer<A>
Creates a Reducer from a combine function and an initialValue.
When to use
Use when you have a custom reducing operation not covered by a pre-built reducer.
- You want to provide an optimized
combineAll (e.g. short-circuiting on
a known absorbing element like 0 for multiplication).
Details
- If
combineAll is omitted, a default left-to-right fold starting from
initialValue is used.
- If
combineAll is provided, it completely replaces the default fold.
Example (Multiplying with short-circuit)
import { Reducer } from "effect"
const Product = Reducer.make<number>(
(a, b) => a * b,
1,
(collection) => {
let acc = 1
for (const n of collection) {
if (n === 0) return 0
acc *= n
}
return acc
}
)
console.log(Product.combineAll([2, 3, 4]))
// Output: 24
console.log(Product.combineAll([2, 0, 4]))
// Output: 0
make((a: biginta, b: bigintb) => a: biginta * b: bigintb, const bigint1: bigintbigint1, (collection: Iterable<bigint>collection) => {
let let acc: bigintacc = const bigint1: bigintbigint1
for (const const n: bigintn of collection: Iterable<bigint>collection) {
if (const n: bigintn === const bigint0: bigintbigint0) return const bigint0: bigintbigint0
let acc: bigintacc *= const n: bigintn
}
return let acc: bigintacc
})